## Four forces acting on a hook are shown in the figure. Determine the direction of the force 150N such that the hook is pulled in a direction. Determine the resulting force in the x-direction

\begin{equation*}

\sum Fy = 0\\

\end{equation*}

-80sin45 +60sin60 +100sin30 + 150sinθ = 0

θ = 17.61°

\begin{equation*}

\sum Fx = Rx\\

\end{equation*}

= 80cos45 +60cos60 +100cos30 + 150cos17.61 = Rx

Rx = 316.142KN